- Here's the problem that I'm trying to solve using the
**greedy**algorithm: Given a value V, we want to make**change**for V rupees. We have infinite supply of each of the denominations in Indian currency. i.e. we have infinite supply of {1,2,5,10,20,50,100,200,500,2000} valued**coins**/notes What is the minimum number of**coins**and/or notes needed to .... The**coin**-**change**problem - And to print it, you just go: System.out.println ("Total
**coins**needed: " +coinChangeGreedy (**coins**, n)); Additionally - if you want to keep track of**coins**used, you can store them in an ArrayList every time it is chosen. list.add (**coins**[i]). And of course you declare and initialize that list` at the beggining. Share. - So I'm prepping for an algorithms exam and I am not sure why the
**coin change**algorithm produces an optimal solution. In addition the old British coinage system won't produce an optimal solution with the**Greedy**algorithm i.e. the C2 = [100, 30, 24 so I know the test (i think), but I don't know the**proof**. Sep 02, 2019 · Initialize set of**coins**as empty. S = {} 3. - Total
**coins**needed = 3 (25+25+20). In this approach, we are not bothering about the overall result. We just pick the best option in each step and hoping that it might. Sep 04, 2019 · Enter you amount: 70. Following is minimal number of**change**for 70: 20 20 20 10. Time complexity of the**greedy coin change**algorithm will be: For sorting n**coins**O